Changeset 6438 for trunk/MagicSoft
- Timestamp:
- 02/13/05 21:15:20 (20 years ago)
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trunk/MagicSoft/TDAS-Extractor/Pedestal.tex
r6417 r6438 114 114 \item Determine $MSE$ from the fitted error of $\widehat{S}$, which is possible for the 115 115 fit and the digital filter (eq.~\ref{eq:of_noise}). 116 In prin icple, all dependencies can be retrieved with this method.116 In principle, all dependencies can be retrieved with this method. 117 117 \end{enumerate} 118 118 … … 363 363 Figures~\ref{fig:sw:distped} through~\ref{fig:df:distped} show the 364 364 extracted pedestal distributions for some selected extractors (\#18, \#23, \#25 and \#28) 365 for one ex amplary channel (pixel 100) and two background situations: Closed camera with only electronic365 for one exemplary channel (pixel 100) and two background situations: Closed camera with only electronic 366 366 noise and open camera pointing to an extra-galactic source. 367 367 One can see the (asymmetric) Poisson behaviour of the … … 413 413 (pixel 100). The result obtained from a simple addition of 2 FADC 414 414 slice contents (``fundamental'') is displayed as red histogram, the one obtained from the application 415 of time-randomized weig ths on a fixed window of 2 FADC slices as blue histogram and the one obtained from the415 of time-randomized weights on a fixed window of 2 FADC slices as blue histogram and the one obtained from the 416 416 full algorithm allowed to slide within a global window of 12 slices. The obtained histogram means and 417 417 RMSs have been converted to equiv. photo-electrons.} … … 428 428 (pixel 100). The result obtained from a simple addition of 6 FADC 429 429 slice contents (``fundamental'') is displayed as red histogram, the one obtained from the application 430 of time-randomized weig ths on a fixed window of 6 slices as blue histogram and the one obtained from the430 of time-randomized weights on a fixed window of 6 slices as blue histogram and the one obtained from the 431 431 full algorithm allowed to slide within a global window of 12 slices. The obtained histogram means and 432 432 RMSs have been converted to equiv. photo-electrons.} … … 514 514 \end{equation} 515 515 516 We tested this relation assuming that the fitted area underneath the pedestal peak $Area_0$ is516 We tested this relation assuming that the fitted area underneath the pedestal peak Area$_0$ is 517 517 proportional to $P(0)$ and the sum of the fitted areas underneath the single photo-electron peak 518 $Area_1$ and the double photo-electron peak $Area_2$ proportional to $P(>0)$. Thus, one expects:519 520 \begin{equation} 521 Area_0 / (Area_1 + Area+2 ) = \frac{e^{-R\cdot WS}}{1-e^{-R\cdot WS}}518 Area$_1$ and the double photo-electron peak Area$_2$ proportional to $P(>0)$. Thus, one expects: 519 520 \begin{equation} 521 \mathrm{Area}_0 / (\mathrm{Area}_1 + \mathrm{Area}_2 ) = \frac{e^{-R\cdot WS}}{1-e^{-R\cdot WS}} 522 522 \end{equation} 523 523
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