# Changes between Version 71 and Version 72 of DatabaseBasedAnalysis/Spectrum

Ignore:
Timestamp:
Dec 4, 2019, 11:45:58 AM (12 months ago)
Comment:

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### Legend:

Unmodified
 v71 $\sigma^2(N_\textrm{exc}^\textrm{MC}) = \left(\frac{dN_\textrm{exc}^\textrm{MC}}{dN_\textrm{sig}^\textrm{MC}}\right)^2\sigma^2(N_\textrm{sig}^\textrm{MC}) + \left(\frac{dN_\textrm{exc}^\textrm{MC}}{d\hat N_\textrm{bg}^\textrm{MC}}\right)^2\sigma^2(\hat N_\textrm{bg}^\textrm{MC})$ $\sigma^2(N_\textrm{exc}) = \left(\frac{dN_\textrm{exc}}{dN_\textrm{sig}}\right)^2\sigma^2(N_\textrm{sig}) + \left(\frac{dN_\textrm{exc}}{d\hat N_\textrm{bg}}\right)^2\sigma^2(\hat N_\textrm{bg})$ $\sigma^2(N_\textrm{exc}) = \left(\frac{dN_\textrm{exc}}{dN_\textrm{sig}}\right)^2\sigma^2(N_\textrm{sig}) + \left(\frac{dN_\textrm{exc}}{d\hat N_\textrm{bg}}\right)^2\sigma^2(\hat N_\textrm{bg}) = N_\textrm{sig} + \frac{1}{5^2}N_\textrm{bg}$ $\sigma^2(N_\textrm{sig}) = N_\textrm{sig}$ $\sigma^2(\hat N_\textrm{bg}) = \frac{1}{5^2}\sigma^2(N_\textrm{bg}) = \frac{1}{5^2} N_\textrm{bg}$ $\sigma^2(\hat N_\textrm{bg}) = \frac{1}{5^2}\sigma^2(N_\textrm{bg}) = \frac{1}{5^2} N_\textrm{bg}$ $\sigma^2(N_\textrm{sig}^\textrm{MC}) = \sum_\textrm{sig}^\textrm{MC}\omega^2_i(E)\omega^2_i(\theta)$