34 | | \[\sigma^2(N_\textrm{exc}) = \left(\frac{dN_\textrm{exc}}{dN_\textrm{sig}}\right)^2\sigma^2(N_\textrm{sig}) + \left(\frac{dN_\textrm{exc}}{d\hat N_\textrm{bg}}\right)^2\sigma^2(\hat N_\textrm{bg}) = N_\textrm{sig} + \frac{1}{5^2}N_\textrm{bg} \] |
| 34 | \[\sigma^2(N_\textrm{exc}) = \left(\frac{dN_\textrm{exc}}{dN_\textrm{sig}}\right)^2\sigma^2(N_\textrm{sig}) + \left(\frac{dN_\textrm{exc}}{d\hat N_\textrm{bg}}\right)^2\sigma^2(\hat N_\textrm{bg})\] |
| 35 | |
| 36 | For data this immediately resolves to |
| 37 | |
| 38 | \[\sigma^2(N_\textrm{exc}) = N_\textrm{sig} + \frac{1}{5^2}N_\textrm{bg} \] |
| 39 | |
| 40 | assuming \(\sigma^2(N_\textrm{sig,bg}) = N_\textrm{sig,bg}\). |